At `30^(@)C`, the solubility of `Ag_(2)CO_(3)(K_(sp) = 8 xx 10^(-12))` would be greatest in one liter of
A. `0.05 M Na_(2)CO_(3)`
B. `0.05 M AgNO_(3)`
C. Pure water
D. `0.05 M NH_(3)`
Al(OH)3 \(\leftrightharpoons\) Al+3(aq)+ + 3OH-(aq)
using law of mass action
K = \(\frac{[Al^{+3}][OH^-]^3}{[Al(OH^-)_3]}\)
⇒ K = equilibrium constant
\(\because\) [al(OH)_3] = constant
\(\therefore\) Rearranging above equation.
K x [Al(OH)3] = [Al+3] [OH-]3
⇒ Ksp = [Al+3] [OH-]3
where Ksp = [S] [3S]3
= s x 27S3
Ksp = 27s4
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